3b2≥λb(a b)include 0 bcosA-2ccosB=2bcosC-acosB

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3b2≥λb(a b)include 0 bcosA-2ccosB=2bcosC-acosB
3b2≥λb(a b)include 0 bcosA-2ccosB=2bcosC-acosB

3b2≥λb(a b)include 0 bcosA-2ccosB=2bcosC-acosB
printf()函数中’\n’；’\t’；’\a’(2x-14) / (x^2-1) <= -1因为4〔x-2〕⒉-1=8因为printf()函数中’\n’；’\t’；’\a’