作业帮若√x-1-√1-x=(x+y)²先化简再求值：（1/2x）-(1/x+y)[x²-y²+(x+y/2x]
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/27 20:24:43
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若√x-1-√1-x=(x+y)²先化简再求值：（1/2x）-(1/x+y)[x²-y²+(x+y/2x]
若√x-1-√1-x=(x+y)²先化简再求值：（1/2x）-(1/x+y)[x²-y²+(x+y/2x]
若√x-1-√1-x=(x+y)²先化简再求值：（1/2x）-(1/x+y)[x²-y²+(x+y/2x]
是√(x-1)-√(1-x)=(x+y)²吧!
由x-1≥0,且1-x≥0,得x=1,所以x+y=0,得y= -1.
原式=1/2-(1-1)[1-1+(1-1/2)]=1/2.