(1)(x+y)^2-(x+y)^3(2)(x-y)-(x-y)^3(3)(x-y)^2-(y-x)^3(4)2(x-y)-3(y-x)^2(5)4ab(a=b)^2-6a^2b(a+b)(6)(x+y)^2(x-y)+(x+y)(x-y)^2(7)2a(a-3)^2-6a^2(3-a)+8a(a-3)(8)24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xy(z-x-y)(9)(a-b)(b-a)^n(b-a)^2n-1 [两解）（10）2^2=3,2^b

来源：学生作业帮助网 编辑：作业帮 时间：2024/04/27 17:45:31
(1)(x+y)^2-(x+y)^3(2)(x-y)-(x-y)^3(3)(x-y)^2-(y-x)^3(4)2(x-y)-3(y-x)^2(5)4ab(a=b)^2-6a^2b(a+b)(6)(x+y)^2(x-y)+(x+y)(x-y)^2(7)2a(a-3)^2-6a^2(3-a)+8a(a-3)(8)24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xy(z-x-y)(9)(a-b)(b-a)^n(b-a)^2n-1 [两解）（10）2^2=3,2^b

(1)(x+y)^2-(x+y)^3(2)(x-y)-(x-y)^3(3)(x-y)^2-(y-x)^3(4)2(x-y)-3(y-x)^2(5)4ab(a=b)^2-6a^2b(a+b)(6)(x+y)^2(x-y)+(x+y)(x-y)^2(7)2a(a-3)^2-6a^2(3-a)+8a(a-3)(8)24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xy(z-x-y)(9)(a-b)(b-a)^n(b-a)^2n-1 [两解）（10）2^2=3,2^b
(1)(x+y)^2-(x+y)^3
(2)(x-y)-(x-y)^3
(3)(x-y)^2-(y-x)^3
(4)2(x-y)-3(y-x)^2
(5)4ab(a=b)^2-6a^2b(a+b)
(6)(x+y)^2(x-y)+(x+y)(x-y)^2
(7)2a(a-3)^2-6a^2(3-a)+8a(a-3)
(8)24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xy(z-x-y)
(9)(a-b)(b-a)^n(b-a)^2n-1 [两解）
（10）2^2=3,2^b=6,2^c=12,求a,b,c之间的一个数量关系[两解）

(1)(x+y)^2-(x+y)^3(2)(x-y)-(x-y)^3(3)(x-y)^2-(y-x)^3(4)2(x-y)-3(y-x)^2(5)4ab(a=b)^2-6a^2b(a+b)(6)(x+y)^2(x-y)+(x+y)(x-y)^2(7)2a(a-3)^2-6a^2(3-a)+8a(a-3)(8)24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xy(z-x-y)(9)(a-b)(b-a)^n(b-a)^2n-1 [两解）（10）2^2=3,2^b
(1)(x+y)^2-(x+y)^3
=(x+y)^2-(x+y)(x+y)^2
=(1-x-y)(x+y)^2
(2)(x-y)-(x-y)^3
=(x-y)-(x-y)(x-y)^2
=(1-x+y)(x-y)^2
(3)(x-y)^2-(y-x)^3
=(y-x)^2-(y-x)(y-x)^2
=(1-y+x)(y-x)^2
(4)2(x-y)-3(y-x)^2
=2(x-y)-3(x-y)^2
=2(x-y)-3(x-y)(x-y)
=(2-3x+3y)(x-y)
(5)4ab(a=b)^2-6a^2b(a+b)
=4ab(a+b)(a+b)-6aab(a+b)
=2ab(a+b)(2a+2b-3a)
=2ab(a+b)(2b-a)
(6)(x+y)^2(x-y)+(x+y)(x-y)^2
=(x+y)(x+y)(x-y)+(x+y)(x-y)(x-y)
=(x+y)(x-y)(x+y+x-y)
2x(x+y)(x-y)
(7)2a(a-3)^2-6a^2(3-a)+8a(a-3)
=2a(a-3)(a-3)+6aa(a-3)+8a(a-3)
=2a(a-3)(a-3+3a+4)
2a(a-3)(4a+1)
(8)24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xy(z-x-y)
=24xyyz^2(x+y-Z)-32xyz(x+y-z)(x+y-z)-8xy(x+y-z)
8xy(x+y-z)[3yz^2-4z(x+y-z)-1]这题你的式子可能写错了
(9)(a-b)(b-a)^n(b-a)^2n-1 [两解）
(a-b)(b-a)^n 和 (b-a)^2n-1之间是不是少了个+或-?
你可以分n是偶数和奇数两种情况做,不难
（10）2^2=3,2^b=6,2^c=12,求a,b,c之间的一个数量关系[两解）
由题知道2^a*4=2^b*2=2^c=12
即2^(a+2)=2^(b+1)=2^c
所以a+2=b+1=c

(x+y)^2-(x+y)^3 =(x+y)^2(1-(x+y))
(x-y)-(x-y)^3= (x-y)(1-(x-y)^2=(x-y)(1+(x-y))(1-(x-y))
(x-y)^2-(y-x)^3 =(x-y)^2(1+(x-y))
2(x-y)-3(y-x)^2=(x-y)(2+3(x-y))

x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x² 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 x(x-y)2-(y-x)3 (3x-y)^2+(3x+y)(3x-y),x=1,y=-2 二元一次方程 ：2(x+y)-(x-y)=3 (x+y)-2(x-y)=1 (x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5) 2(x+y)-3(x-y)=1 6(x+y)+(x-y)=51 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 变量x,y满足约束条件,x+y>=3,x-y>=-1,2x-y (Y-X)^3*(X-Y)^m+(X-Y) ^m+1*(Y-X)^2 (x-y)^2+(x+y)(x-y) 其中 X =3 Y=-1 [2/3x-2/x+y(x+y/3x-x-y)]/x-y/x 化简：{2/3x-2/(x+y)[(x+y)/3x-x-y]}/(x+y)/x 计算2/3x-2/x+y(x+y/3x-x-y)/x-y/x 化简3x-2/(x+y)[(x+y)/3x-x-y]÷(x-y)/x [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y 1、(-7x^y)(2x^y-3xy^3+xy) 2、((x-y)^6)/((y-x)^3)/(x-y) x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=?