(1/2-1)(1//3-1)=( )*( )=( )(1/2-1)(1/3-1)(1/4-1)=( )*( )*( )……根据以上规律,写出下面各式的值(1/2-1)(1/3-1)(1/4-1)……(1/9-1)=(-8008)(1/2002-1)(1/2001-1)……(1/1001-1

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(1/2-1)(1//3-1)=( )*( )=( )(1/2-1)(1/3-1)(1/4-1)=( )*( )*( )……根据以上规律,写出下面各式的值(1/2-1)(1/3-1)(1/4-1)……(1/9-1)=(-8008)(1/2002-1)(1/2001-1)……(1/1001-1

(1/2-1)(1//3-1)=( )*( )=( )(1/2-1)(1/3-1)(1/4-1)=( )*( )*( )……根据以上规律,写出下面各式的值(1/2-1)(1/3-1)(1/4-1)……(1/9-1)=(-8008)(1/2002-1)(1/2001-1)……(1/1001-1
(1/2-1)(1//3-1)=( )*( )=( )
(1/2-1)(1/3-1)(1/4-1)=( )*( )*( )
……
根据以上规律,写出下面各式的值
(1/2-1)(1/3-1)(1/4-1)……(1/9-1)=
(-8008)(1/2002-1)(1/2001-1)……(1/1001-1)=

(1/2-1)(1//3-1)=( )*( )=( )(1/2-1)(1/3-1)(1/4-1)=( )*( )*( )……根据以上规律,写出下面各式的值(1/2-1)(1/3-1)(1/4-1)……(1/9-1)=(-8008)(1/2002-1)(1/2001-1)……(1/1001-1
小孩子这是一个简单的规律题上式等于-1/2*-3/2...*-n/n+1=(-1)^n*1/n+1所以答案是#-1/1002

(1+1/2)×(1-1/2)×(1+1/3)×(1-1/3)×...×(1+1/99)×(1-1/99)=? (1+1/2)×(1-1/2)×(1+1/3)×(1-1/3)×……×(1+1/99)×(1-1/99)= 填空(填数字)(1/2-1)(1/3-1)=( )×( )=( );(1/2-1)(1/3-1)(1/4-1)=( )×( )×( )=( );(1/2-1)(1/3-1)(1/4-1)(1/5-1)=( )×( )×( )×( )=( );例:(1/2-1)(1/3-1)=( )×( )=( )前两个括号填1/2-1的结果 |3×(-1)+2|=1对吗 (1-2*2/1)*(1-3*3/1)*(1-4*4/1)*...*(1-2004*2004/1)*(1-2005*2005/1)=?要过程! 1.(1+1/2+1/3+1/4)*(1/2+1/3+1/4+1/5)-(1+1/2+1/3+1/4+1/5)*(1/2+1/3+1/4)=2.(1+1/2+1/3+1/4+1/5)*(1/2+1/3+1/4+1/5+1/6)-(1+1/2+1/3+1/4+1/5+1/6)*(1/2+1/3+1/4+1/5)= 数列 1+(1+2)+(1+2+3)+(1+2+3+4)+.+(1+2+3+...+2009)=? 2(x+1)-1/2(x-1)=3(x-1)-1/3(x+1)方程 计算:1/(1*3)+1/(3*5)+1/(5*7)+…+1/(49*51).因为1/(1*2)=1-(1/2),1/(2*3)=(1/2)*(1/3),1/(3*4)=(1/3)-(1/4),……,1/(9*10)=(1/9)-(1/10).所以1/(1*2)+1/(2*3)+1/(3*4)+…+1/(9 1/1*3=1/2(1-1/3)1/3*5=1/2(1/3-1/5)1/5*7=1/2(1/5-1/7).1/17*19=1/2(1/17-1/19)所以1/1*3+1/3*5+1/5*7+.1/17*19=1/2(1-1/3)+1/2(1/3+1/5)+1/2(1/5-1/7)+.1/2(1/17-1/19)=1/2(1-1/3+1/3-1/5+1/5-1/7+1/7.+1/17-1/19)=1/2(1-1/1 (1+1/2)*(1+1/4)*.(1+1/10)*(1-1/3)*(1-1/5)*.(1-1/9)=?请写出过程和道理! -1*(1/2)=-1+(1/2),-(1/2)+(1/3)=-(1/2)+(1/3),-(1/3)*(1/4)=-(1/3)+(1/4),.规律(1)规律:( )用含n的式子表示,n为正整数.(2)运用以上规律计算:(-1*(1/2))+(-(1/2)*(1/3))+(-(1/3)*(1/4))+.+(- (1×2×3×…×2005)×(-1/2)×(-1/3)×(-1/4)×...×(-1/2005)=? (1-1/2²)(1-1/3²)(1-1/4²).(1-1/10²)=? (1-1/2)+ (1/3-1/4)+ (1/5-1/6)...+ (1/99-1/100)=? (1) 1+(-2)+3+(-4)+5+(-6)+.+99+(-100)=?(2)(1-1/2)+(1/2-1/3)+(1/3-1/4)+.+(1/1999-1/2000)=? 1/2×( )=( )×18/7=1×( )=3×( )=1 一道高中数列求和题1+1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+...+1/(1+2+3+...99)=?