如果2x-y=10,求代数式[(x²+y²)-(x-y)²+2y(x-y)]÷4y的值

如果2x-y=10,求代数式[(x²+y²)-(x-y)²+2y(x-y)]÷4y的值
如果2x-y=10,求代数式[(x²+y²)-(x-y)²+2y(x-y)]÷4y的值

如果2x-y=10,求代数式[(x²+y²)-(x-y)²+2y(x-y)]÷4y的值
如果2x-y=10
那么[(x²+y²)-(x-y)²+2y(x-y)]÷4y
=[(x²+y²)-(x²-2xy+y²)+(2xy-2y²)]÷4y
=(4xy-2y²)÷4y
=(2x-y)/2
=10/2
=5
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