16/x :18/(x+2)=4 :3

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 11:24:52
16/x :18/(x+2)=4 :3

16/x :18/(x+2)=4 :3
16/x :18/(x+2)=4 :3

16/x :18/(x+2)=4 :3
16/x :18/(x+2)=4 :3
16/x ×3= 18/(x+2)×4
48/x=72/(x+2)
72x=48×(x+2)
72x-48x=96
24x=96
x=4

16/x : 18/(x+2)=4 :3
16/x * 3=18/(x+2)*4
48/X=72/(X+2)
两边同乘以X(x+2),得
48*(x+2)=72X
48x+98=72X
24X=98
X=13/4

x=4

16/x * x+2/18=4/3
(16x+32)/18x=4/3
16x+32=18x *4/3
16x+32=24x
8x=32
x=4

matlab解数值分析题p=(x-1)*(x-2)*(x-3)*(x-4)*(x-5)*(x-6)*(x-7)*(x-8)*(x-9)*(x-10)*(x-11)*(x-12)*(x-13)*(x-14)*(x-15)*(x-16)*(x-17)*(x-18)*(x-19)*(x-20)解为1,2,3……,20取多个非常小的数用软件工具求解方程p(x)+n*x^19=0,并 matlab解决约束非线性规划问题myfun.mfunction f=myfun(x)f=x(1)*x(13)+x(2)*x(14)+x(3)*x(15)+x(25)+1.697*(x(4)*x(16)+...x(5)*x(17)+x(6)*x(18)+x(26))+0.575*(x(7)*x(19)+x(8)*x(20)...+x(9)*x(21)+x(27))+0.723*(x(10)*x(22)+x(11)*x(23)+x(12)*x(24)); matlab解决约束非线性规划问题myfun.mfunction f=myfun(x)f=x(1)*x(13)+x(2)*x(14)+x(3)*x(15)+x(25)+1.697*(x(4)*x(16)+...x(5)*x(17)+x(6)*x(18)+x(26))+0.575*(x(7)*x(19)+x(8)*x(20)...+x(9)*x(21)+x(27))+0.723*(x(10)*x(22)+x(11)*x(23)+x(12)*x(24)); [(1+x)^20+(1+x)^19+(1+x)^18+(1+x)^17+(1+x)^16+(1+x)^15+(1+x)^14+(1+x)^13+(1+x)^12+(1+x)^11+(1+x)^10+(1+x)^ 9+(1+x)^8+(1+x)^7+(1+x)^6+(1+x)^5+(1+x)^4+(1+x)^3+(1+x)^2+(1+x)]=28.51 (16x^4+4x^2+x)/x=? (x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3) (1)X-3/X-1+X²-2/(x-1)(X-7)=1+x-5/x-7 (2)2x-1/x+4-5=96/x²-16-1-3x/4-x x=根号17-1 求x^5+2x^4-17x^3-x^2+18x-16 解方程:(x-8)/(x-3)-(x-9)/(x-4)=(x+7)/(x+8)-(x+2)/(x+3) 4+6X(3x-2)=16x 怎么解方程?注备:X=乘 x=x 解方程:(x^2+3x+1)/(4x^2+16x-1)-(12x^2+18x-3)/(x^2+3x+1)=2 请假一下可否用lingo如何求解下面的非线性0-1规划的解?目标函数是:f=300000/(4364.64*(x(1)+x(2)+x(3)+x(4)+x(5)+x(6))+10392*(x(7)+x(8)+x(9)+x(10)+x(11)+x(12)+x(13)+x(14)+x(15)+x(16)+x(17)+x(18)+x(19)+x(20)+x(21)+x(22)+x(23)+x(24 1.(x+1)(2x-3)-(x-1)(x+2)=x.x+71.(x+1)(2x-3)-(x-1)(x+2)=x.x+72.(2x+1)(4x.x-2x+1)-2x(4x.x+1)=03.(x-3)(x+2)=x.x-16 4.2-0.6x=3.6x 5x+2x=33.6 7x-4x=0.75 2x+7x+2.1=12 56x-32x-119=361 x+5=2x 3x+9=6x 4x-28=2x 2x+18=7x 5x=25*4-15x 7x-x+2*3=29.4 (28.8+5.5x+3.2)除2=71 已知x=13/(4+根号3),求(x^4-6x^3-2x^2+18x+23)/(x^2-8x+15) 的值 禁止复制粘贴:x=13/(4+√3)=4-√3√3=4-x3=x²-8x+16x^2-8x+13=0,所以x^2-8x+15=2;x^4-6x^3-2x^2+18x+23=x^2(x^2-8x+13)+2x^3-15x^2+18x+23=2x(x^2-8x+13)+x^2-8x+23=x^2-8x+2 解方程;3x(66-3x)=36 16x+6.7-4x=66.7 x+2x/4=18 60%x+25=40 x+30%x=52 19-120%x=7 4分之3x-5%x=17.5 x-10%x=18 (1-25%)x=36 2x+30%x=9.2 设x= -5/2,求6x+(x/x-2 - x/x+2)/4x/x^4-2x^3+8x-16的值