求证:1/7+1/23+.+1/[4n(n+1)-1]

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求证:1/7+1/23+.+1/[4n(n+1)-1]

求证:1/7+1/23+.+1/[4n(n+1)-1]
求证:1/7+1/23+.+1/[4n(n+1)-1]

求证:1/7+1/23+.+1/[4n(n+1)-1]
n≥1时易得n(n+1)≥2,即0.5n(n+1)≥1
所以4n(n+1)-1≥3.5n(n+1)
所以1/[4n(n+1)-1]≤1/[3.5n(n+1)]
1/7+1/23+.+1/[4n(n+1)-1]≤1/7+1/[3.5*2*3]+……+1/[3.5n(n+1)]
=1/7+(1/3.5)[1/(2*3)+……1/(n(n+1))]
=1/7+(1/3.5)[1/2-1/3+1/3-1/4+……+1/n-1/(n+1)]
=1/7+(1/3.5)[1/2-1/(n+1)]
≤1/7+(1/3.5)*1/2
=1/7+1/7=2/7