lim x→0(1+2cosx)^secx

lim(x→0)(ln(1+x^2)/(sec-cosx))这题怎么解哈 大哥大姐帮帮忙啊 lim sec^2~x→0 求lim (sec^2 x求极限lim (sec^2 x - 1 )/(1-cos x) X-0请写出过程, 求lim(1-cosx)/x^2求lim(1-COSX)/X^2X→0 lim(x→0)(cosx)^(1/ln(1+x^2)) 求Lim(x→0)(sinx/x)^(cosx/1-cosx) lim(x→0)(1/cosx)=? lim(n>无穷)sec(x/2)sec(x/2^2)``````````sec(x/2^n) (x不等于0) 的极限 limx→0(cosx)^(1/x^2)求解lim(x→0)((cosx)^(1/x^2)) lim(x→0)[(secx)^2-1] /(1-cosx) lim x→0(1+2cosx)^secx 求极限：lim（x→0）ln(1+x²）/ (sec x- cos x) lim x趋向于0,sec^2*x等于什么? 求极限lim(x→1) (2-x)^[sec(πx/2)]. 求下列极限 lim（x→0）(1-cosx*√cosx*cosx的立方根)/x^2 lim(x→0)(cosx-cos^2x)/x^2 lim（x→0） 1-cosx/x＋x lim(x→0)(e^x-cosx)/x=1?