解不等式:(1-3x)^2+(2x-1)^2>=13(x-1)(x+1)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/08 08:19:41
解不等式:(1-3x)^2+(2x-1)^2>=13(x-1)(x+1)

解不等式:(1-3x)^2+(2x-1)^2>=13(x-1)(x+1)
解不等式:(1-3x)^2+(2x-1)^2>=13(x-1)(x+1)

解不等式:(1-3x)^2+(2x-1)^2>=13(x-1)(x+1)
(1-3x)^2+(2x-1)^2≥13(x-1)(x+1)
1-6x+9x^2+4x^2-4x+1≥ 13x^2-13
13x^2-13x^2+6x+4x≤1+1+13
10x≤15
x≤1.5

x,<=3/2

:(1-3x)^2+(2x-1)^2>=13(x-1)(x+1)
1-6x+9x²+4x²-4x+1≥13x²-13
9x²+4x²-13x²-6x-4x≥-13-1-1
-10x≥-15
x≤1.5

:1-6x+9x²+4x²-4X+4>=13x²-1
-10X≥-15
X≤3/2

1+9x^2-6x+4x^2+1-4x>=13(x^2-1)
13x^2-10x+2>=13(x^2-1)
x<=1.5

由题知:1-6x+9x^2+4x^2-4x+1>13x^2-13所以整理得:-10x>-15所以得:x>1.5

1-3x)^2+(2x-1)^2≥13(x-1)(x+1)
1-6x+9x^2+4x^2-4x+1≥ 13x^2-13
13x^2-13x^2+6x+4x≤1+1+13
10x≤15
x≤1.5