将y=(x^3-2x)/(x^2+x-2)展开成x+1的幂级数怎么展开?

3^x+2x=y,x x-y/x+y=-1/2,x*x-xy-2y*y/x*x-3xy+2y*y的解是多少?同上,请将过程写出, 将y=-2x²-3x配方 x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 [2/3x-2/x+y(x+y/3x-x-y)]/x-y/x 化简：{2/3x-2/(x+y)[(x+y)/3x-x-y]}/(x+y)/x 计算2/3x-2/x+y(x+y/3x-x-y)/x-y/x 化简3x-2/(x+y)[(x+y)/3x-x-y]÷(x-y)/x x(x-y)2-(y-x)3 将(x-y)看成一个整体,将3(x-y)²-4(x-y)+7(x-y)-6(y-x)²-2(y-x)合并同类项. 将y=(x^3-2x)/(x^2+x-2)展开成x+1的幂级数怎么展开? 函数,y=3x/(x^2+x+1) ,x 函数y=3x/(x^2+x+1) （x (x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)= (x+y)(x-y)+(x-y)平方-(x-y)(3x-y) 其中x=-2 y=3分之一 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) 化简 3x(x^2-x-1)-(x+1)(3x^-x) X^3(x-y)+x(y-x) (x+y)(2x-3y)=?