exchang a for b与substitute A for B区别

exchang a for b与substitute A for B区别 英语exchange 与 replace 的用法差别exchang A for B 是把（ ）换成（ ） replace A with B 是把（ ）换成（ ） a/x armani exchang是什么东西? matlab 最速下降法求解clc;clear;disp('最速下降法')syms x1 x2 lam;x=[x1 x2];t=0; X0=[1;1]; y=(x1^2+x2-11)^2+(x1+x2^2-7)^2;e=0.01;for n=1:10 a=subs(diff(y,x1),x,X0); b=subs(diff(y,x2),x,X0); yj=[a;b]; z=subs(y,x,X0-lam*y matlab程序 解方程组syms a b Rsd Rspf1=72.8*(1+cos(a))-2*(sqrt(51*Rsp)+sqrt(21.8*Rsd));f2=50.8*(1+cos(b))-2*(sqrt(2.3*Rsp)+sqrt(48.5*Rsd));A=input('输入：A=');B=input('输入：B=');for i=1:length(A)a=A(i);b=B(i);f11=subs(f1);f22=subs(f2);[Rs matlab中subs函数subs(sym(f),findsym(sym(f)),a) f是一个函数, iif(subs(a,5,2)=0,SUBS(a,6,1),subs(a,5,2)+月+right(a,急.A=DTOC(DATE(),1)thisform.label.caption=left(A,4)+年+;iif(subs(a,5,2)=0,SUBS(a,6,1),subs(a,5,2)+月+right(a,2)=日中的 iif(subs(a,5,2)=0,SUBS(a,6,1),subs(a,5,2)+月+right(a, matlab计算过程显示function [I,step]=Roberg(f,a,b,eps)if(nargin==3)eps=1.0e-4;end;M=1;tol=10;k=0;T=zeros(1,1);h=b-a;T(1,1)=(h/2)*(subs(sym(f),findsym(sym(f)),a)+subs(sym(f),findsym(sym(f)),b));while tol>epsk=k+1;h=h/2;Q=0;for i=1:Mx=a+h*(2*i-1); prepare for 与 prepare A for B 有何区别 matlab解符号方程Y^2-Z^2=X^2Y+Z-A=0X^2-B*X-C=0我是这样写的:function [x,y,z]=sp(A,B,C)[u,v,w]=solve('y*y-z*z-x*x','y+z-a','x*x-b*x-c')subs(u,[a,b,c],[A,B,C])subs(v,[a,b,c],[A,B,C])subs(w,[a,b,c],[A,B,C])x=uy=v;z=w;运行时提示以下的错 刚接触matlab 麻烦帮忙看下哪里出错了,算出来的结果还带着一个x,程序如下syms xa=300000*0.006b=x-300000*0.006c=0d=0i=0for i=1:239a=(300000-b)*0.006b=x-ac=c+ad=d+bi=i+1end;f=subs(solve('240*x-300000-c',x)) matlab 怎么进行傅里叶级数展开?请问这个函数是怎么进行傅里叶级数展开的?syms x;f=(x-abs(x))/2;xx=-pi:.01:pi;yy=subs(f,x,xx);plot(xx,yy,'-'),hold onfor n=4:4:20 [a,b,f1]=f_series(f,x,n); y1=subs(f1,x,xx); pl When Arnold use dollars to record his income and expenses,he is using money as a a.unit of accounWhen Arnold use dollars to record his income and expenses,he is using money as aa.unit of account.b.means of payment.c.store of value.d.medium of exchang 请各位帮我解释一下这句matlab语句在之前已经算好d2f = [ 6*x + 6,0][ 0,6 - 6*y]还有xx = 1-31-3 yy = 0022下面这句for i=1:length(xx)a=subs(d2f,{x,y},{xx(i),{yy(i)}}) …………就是上面的这句a=subs(d2f,{x,y},{xx(i),{yy(i) MATLAB1、文件程序如下：syms a b xf=exp(a*x)*sin(b*x);f1=subs(f,a,-0.2);f2=subs(f1,b,0.5);V=pi*int(f2*f2,x,0,2*pi)double(V) % 将符号表达式转换为数值数据x=linspace(0,2*pi,20);f=exp(-0.2*x).*sin(0.5*x);figure(1),cylinder(f) 第9行[ 1、文件程序如下：syms a b xf=exp(a*x)*sin(b*x);f1=subs(f,a,-0.2);f2=subs(f1,b,0.5);V=pi*int(f2*f2,x,0,2*pi)double(V) % 将符号表达式转换为数值数据x=linspace(0,2*pi,20);f=exp(-0.2*x).*sin(0.5*x);figure(1),cylinder(f) 黄金分割法matlab程序错误f=x^2+2*x,给定搜索区间[-3,5],求此函数的极小点.>> a=-3;b=5;e=0.00001;f=@(x)x^2+2*x然后M程序是function xmin=golden(f,a,b,e)k=0;while b-a>e %循环条件y1=subs(f,a1);y2=subs(f,a2);if y1>y2 %比较插 我想根据y函数的初始条件求系数u0,v0 下面是我用matlab写的代码,但一直报错.郁闷死.syms a b t u0 v0a=1;b=2;y=a*u0*t+b*v0*(t+1)^2;dy=diff(y,t);y0=subs(y,t,0);dy0=subs(dy,t,0);[u0,v0]=solve('y0=2','y0=4','u0,v0');最后一行