T=[(b/a)+(d/c)]

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T=[(b/a)+(d/c)]

T=[(b/a)+(d/c)]
T=[(b/a)+(d/c)]

T=[(b/a)+(d/c)]
因为abcd全是正整数,所以高中阶段的不等式方面的公式定理基本全部瘫痪,只有另辟蹊径!我想到的最简单的就是用线性规划来解.下面大体说说我的思路:
原来的问题等价于(x/a)+(y/c)

找专业老师去,在网络找答案,浪费好多时间的!
我做了半天,也没有算出来!

可以先把式子化成:bc+ad

都是整数了完全可以凑的

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