1.已知x2-xy=5,xy-y2=-3.求式子3(x2-xy-xy+y2)的值2.已知x-y=3,xy=5,则代数式(3x-4y+5xy)-(2x-3y)+5xy的值是()

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1.已知x2-xy=5,xy-y2=-3.求式子3(x2-xy-xy+y2)的值2.已知x-y=3,xy=5,则代数式(3x-4y+5xy)-(2x-3y)+5xy的值是()

1.已知x2-xy=5,xy-y2=-3.求式子3(x2-xy-xy+y2)的值2.已知x-y=3,xy=5,则代数式(3x-4y+5xy)-(2x-3y)+5xy的值是()
1.已知x2-xy=5,xy-y2=-3.求式子3(x2-xy-xy+y2)的值
2.已知x-y=3,xy=5,则代数式(3x-4y+5xy)-(2x-3y)+5xy的值是()

1.已知x2-xy=5,xy-y2=-3.求式子3(x2-xy-xy+y2)的值2.已知x-y=3,xy=5,则代数式(3x-4y+5xy)-(2x-3y)+5xy的值是()
1、两个式子相减:
x2-xy-(xy-y2)=5-(-3)
x2-xy-xy+y2=8
所以:3( x2-xy-xy+y2)=8×3=24
2、(3x-4y+5xy)-(2x-3y)+5xy
=3x-4y+5xy-2x+3y+5xy
=x-y+10xy
=3+10×5
=3+50
=53

xy-y2=-3=-y2+xy=3 3(xw-xy+y2)=24

1.原式=3(x2-xy-(xy-y2))=...
2.原式=x-y+10xy=...
童靴,自己代入噢。

1·因为x2-xy-xy+y2=x2-xy-(xy-y2)=5-(-3)=8
原式=24
2·原式=x-y+10xy=3+50=53

1:3(x2-xy-xy+y2)=3[(x2-xy)-(xy-y2)]=3x[5-(-3)]=24.
2:(3x-4y+5xy)-(2x-3y)+5xy=3x