已知x-y-3绝对值+(2x+2y+10)的平方=0,则(x+y)(x-Y)=

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 10:57:01
已知x-y-3绝对值+(2x+2y+10)的平方=0,则(x+y)(x-Y)=

已知x-y-3绝对值+(2x+2y+10)的平方=0,则(x+y)(x-Y)=
已知x-y-3绝对值+(2x+2y+10)的平方=0,则(x+y)(x-Y)=

已知x-y-3绝对值+(2x+2y+10)的平方=0,则(x+y)(x-Y)=
x-y-3绝对值+(2x+2y+10)的平方=0
X-Y-3=0
X-Y=3
2X+2Y+10=0
X+Y=-5
(x+y)(x-Y)
=3X(-5)
=-15

x-y-3绝对值+(2x+2y+10)的平方=0,因为绝对值和平方都不会是负数所以肯定x-y-3=0和2x+2y+10=0所以x=1,y=-4可以得出(x+y)(x-Y)=-15

x-y-3绝对值+(2x+2y+10)的平方=0
x-y-3=0 x-y=3
2x+2y+10=0 x+y=-5
(x+y)(x-y)=-5×3=-15