已知x-1的绝对值与y-2的绝对值互为相反数,计算1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/04 05:32:05
已知x-1的绝对值与y-2的绝对值互为相反数,计算1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+

已知x-1的绝对值与y-2的绝对值互为相反数,计算1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+
已知x-1的绝对值与y-2的绝对值互为相反数,计算1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+

已知x-1的绝对值与y-2的绝对值互为相反数,计算1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+
x=1 y=1代入就好了

要求的式子1/xy+1/(x+1)(y+1)+1/(x+2)(y+2)+,中间空格处有符号没?后面加号完了没??

x-1=0,y-2=0
x=1,y=2
后面的自己算